#include<stdio.h>
 
double add3(double x) 
{
        return x+3; 
}
 
double mysum(double *a, int n) 
{
	double sum = 0.0;
	for(int i = 0;i < n;i++)
        sum+ = a[i]+add3(a[i]);
	return sum; 
}
 
double init(double *a,int n) 
{
	double res; 
	for (int i = 0;i < n;i++) a[i] = (double)i/(double)1000;
	res = mysum(a,n);
	return res; 
}
 
int main()
{
	double res,mysum;
	int n = 20000;
	double a[n];
 
	for (int i = 0;i < n;i++){
        res = init(a,n);
	}
	printf("Result %f\n",res);
	return 0;
}